import re
def compare_strings(string1, string2):
  #Convert both strings to lowercase 
  #and remove leading and trailing blanks
  string1 = string1.lower().strip()
  string2 = string2.lower().strip()

  #Ignore punctuation 就是下面的都加斜線就對了
  punctuation = r"[\.\?\!\,\;\:\-\']"
  string1 = re.sub(punctuation, r"", string1)
  string2 = re.sub(punctuation, r"", string2)

  #DEBUG CODE GOES HERE
  #print(___)

  return string1 == string2

print(compare_strings("Have a Great Day!", "Have a great day?")) # True
print(compare_strings("It's raining again.", "its raining, again")) # True
print(compare_strings("Learn to count: 1, 2, 3.", "Learn to count: one, two, three.")) # False
print(compare_strings("They found some body.", "They found somebody.")) # False

import datetime
from datetime import date

def add_year(date_obj):
  try:
    new_date_obj = date_obj.replace(year = date_obj.year + 1)
  except ValueError:
    # This gets executed when the above method fails, 
    # which means that we're making a Leap Year calculation
    new_date_obj = date_obj.replace(year = date_obj.year + 4)
  return new_date_obj

def next_date(date_string):
  # Convert the argument from string to date object
  date_obj = datetime.datetime.strptime(date_string, r"%Y-%m-%d")
  next_date_obj = add_year(date_obj)

  # Convert the datetime object to string, 
  # in the format of "yyyy-mm-dd" 就是這個下面不能輸入
  next_date_string = next_date_obj.strftime("%Y-%m-%d")
  #print (next_date_string)
  return next_date_string

today = date.today()  # Get today's date
print(next_date(str(today))) 
# Should return a year from today, unless today is Leap Day

print(next_date("2021-01-01")) # Should return 2022-01-01
print(next_date("2020-02-29")) # Should return 2024-02-29